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96=96x^2-56x
We move all terms to the left:
96-(96x^2-56x)=0
We get rid of parentheses
-96x^2+56x+96=0
a = -96; b = 56; c = +96;
Δ = b2-4ac
Δ = 562-4·(-96)·96
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40000}=200$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-200}{2*-96}=\frac{-256}{-192} =1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+200}{2*-96}=\frac{144}{-192} =-3/4 $
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